直播:后台 JWT 推流、前台画中画;WebRTC 服务与 Nginx WebSocket 代理
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109
server/vendor/github.com/pion/srtp/v2/srtp.go
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vendored
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109
server/vendor/github.com/pion/srtp/v2/srtp.go
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// SPDX-FileCopyrightText: 2023 The Pion community <https://pion.ly>
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// SPDX-License-Identifier: MIT
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// Package srtp implements Secure Real-time Transport Protocol
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package srtp
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import (
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"fmt"
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"github.com/pion/rtp"
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)
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func (c *Context) decryptRTP(dst, ciphertext []byte, header *rtp.Header, headerLen int) ([]byte, error) {
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authTagLen, err := c.cipher.AuthTagRTPLen()
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if err != nil {
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return nil, err
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}
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aeadAuthTagLen, err := c.cipher.AEADAuthTagLen()
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if err != nil {
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return nil, err
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}
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mkiLen := len(c.sendMKI)
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// Verify that encrypted packet is long enough
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if len(ciphertext) < (headerLen + aeadAuthTagLen + mkiLen + authTagLen) {
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return nil, fmt.Errorf("%w: %d", errTooShortRTP, len(ciphertext))
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}
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s := c.getSRTPSSRCState(header.SSRC)
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roc, diff, _ := s.nextRolloverCount(header.SequenceNumber)
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markAsValid, ok := s.replayDetector.Check(
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(uint64(roc) << 16) | uint64(header.SequenceNumber),
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)
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if !ok {
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return nil, &duplicatedError{
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Proto: "srtp", SSRC: header.SSRC, Index: uint32(header.SequenceNumber),
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}
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}
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cipher := c.cipher
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if len(c.mkis) > 0 {
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// Find cipher for MKI
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actualMKI := c.cipher.getMKI(ciphertext, true)
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cipher, ok = c.mkis[string(actualMKI)]
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if !ok {
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return nil, ErrMKINotFound
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}
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}
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dst = growBufferSize(dst, len(ciphertext)-authTagLen-len(c.sendMKI))
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dst, err = cipher.decryptRTP(dst, ciphertext, header, headerLen, roc)
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if err != nil {
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return nil, err
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}
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markAsValid()
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s.updateRolloverCount(header.SequenceNumber, diff)
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return dst, nil
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}
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// DecryptRTP decrypts a RTP packet with an encrypted payload
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func (c *Context) DecryptRTP(dst, encrypted []byte, header *rtp.Header) ([]byte, error) {
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if header == nil {
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header = &rtp.Header{}
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}
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headerLen, err := header.Unmarshal(encrypted)
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if err != nil {
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return nil, err
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}
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return c.decryptRTP(dst, encrypted, header, headerLen)
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}
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// EncryptRTP marshals and encrypts an RTP packet, writing to the dst buffer provided.
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// If the dst buffer does not have the capacity to hold `len(plaintext) + 10` bytes, a new one will be allocated and returned.
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// If a rtp.Header is provided, it will be Unmarshaled using the plaintext.
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func (c *Context) EncryptRTP(dst []byte, plaintext []byte, header *rtp.Header) ([]byte, error) {
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if header == nil {
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header = &rtp.Header{}
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}
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headerLen, err := header.Unmarshal(plaintext)
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if err != nil {
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return nil, err
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}
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return c.encryptRTP(dst, header, plaintext[headerLen:])
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}
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// encryptRTP marshals and encrypts an RTP packet, writing to the dst buffer provided.
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// If the dst buffer does not have the capacity, a new one will be allocated and returned.
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// Similar to above but faster because it can avoid unmarshaling the header and marshaling the payload.
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func (c *Context) encryptRTP(dst []byte, header *rtp.Header, payload []byte) (ciphertext []byte, err error) {
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s := c.getSRTPSSRCState(header.SSRC)
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roc, diff, ovf := s.nextRolloverCount(header.SequenceNumber)
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if ovf {
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// ... when 2^48 SRTP packets or 2^31 SRTCP packets have been secured with the same key
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// (whichever occurs before), the key management MUST be called to provide new master key(s)
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// (previously stored and used keys MUST NOT be used again), or the session MUST be terminated.
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// https://www.rfc-editor.org/rfc/rfc3711#section-9.2
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return nil, errExceededMaxPackets
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}
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s.updateRolloverCount(header.SequenceNumber, diff)
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return c.cipher.encryptRTP(dst, header, payload, roc)
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}
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